Heat Transfer Questions & Answers  
Question by Student 201127151
Professor, I have a question about the log mean temperature difference. You explained the LMTD EG :
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And Solving the example, you used the following equations : \begin{equation} q_w = \frac{h A_{s}(T_{b1}-T_{b2})}{\rm{ln}(\frac{T_{w}-T_{b2}}{T_{w}-T_{b1}})} \end{equation} and \begin{equation} q_{in} = \dot{m}c_{p}(T_{b2}-T_{b1}). \end{equation} When heat is transferred to the pipe, I think that the equation (1) and (2) have positive values. If so, I think that the equation (1) is directly equal to the equation (2). But you used a negative sign as follow : $$ \dot{m}c_{p}(T_{b2}-T_{b1}) = - \frac{h A_{s}(T_{b1}-T_{b2})}{\rm{ln}(\frac{T_{w}-T_{b2}}{T_{w}-T_{b1}})} $$ Which one is correct?
06.02.17
Yes, $q_{\rm w}=q_{\rm in}$. The following is wrong: $$ \dot{m}c_{p}(T_{b2}-T_{b1}) = - \frac{h A_{s}(T_{b1}-T_{b2})}{\rm{ln}(\frac{T_{w}-T_{b2}}{T_{w}-T_{b1}})} $$ I guess I meant: $$ \dot{m}c_{p}(T_{b2}-T_{b1}) = - \frac{h A_{s}(T_{b2}-T_{b1})}{\rm{ln}(\frac{T_{w}-T_{b2}}{T_{w}-T_{b1}})} $$ Change the sign if necessary. 2 points bonus.
Question by Student 201227127
professor, I don't understand question 4 of Assignment 8. there is a phrase 'to appose negligible resistance to heat flow.' what does it mean? I think that this means there is no contact conductance. Is it right?
06.06.17
This means the heat resistance of the pipe material itself is small.. Not that there is no contact conductance. 1 point bonus.
Question by Student 201427132
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Dear professor, I have question on "Temperature profile sketch".
I am curious that why $\frac{dT}{dx}$ on graph is decreasing between section $L_A$ and section $L_A$+$L_B$ although there is heat generation between section $L_A$ and section $L_A$+$L_B$.
I guess if there is heat generation, temperature goes up.
But in the graph, it doesn't. Why this happened?
06.15.17
If the temperature would go up, where would the heat go? Left or right?
Question by Student 201427132
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I rewrite my previous question about "Temperature profile sketch".

I am curious that why $\frac{dT}{dx}$ on graph is decreasing between section $L_A$ and section $L_A$+$L_B$ although there is heat generation between section $L_A$ and section $L_A$+$L_B$.
I guess if there is heat generation, temperature goes up.
But in the graph, it doesn't. Why this happened?

There is one assumption that heat always go to right side.
Well yes, but I think the answer to this is fairly obvious.. So, I am asking you to think about it a little. You ask why temperature goes down and not up. But if the temperature goes up, where will the heat go? Answer left or right.
Question by Student 201427132
Dear professor, I have some question about (c) of Question#1, Assignment 5
I assumed flow in between the plates as couette flow ,and derive temperature distribution of fluid from energy equation. :
T=$T_{bot}$+$\frac{\mu {u_{top}}^2 y}{Hk}$(1-$\frac{y}{2H}$) where H is gap width of two plates, $U_{top}$ as velocity of upper plate, and $T_{bot}$ is temperature of lower plate.
Since, T is as form of 2nd order equation ,so I guess that the y=$y_{max}$ where $\frac{dT}{dy}$ is zero is the point that maximum temperature exist.
To get $y_{max}$ I derived $\frac{dT}{dy}$ : $\frac{\mu {u_{top}}^2 }{Hk}$(1- $\frac{y}{H}$ ).
In this equation, $y_{max}$=H. But, correct answer is y=$\frac{H}{2}$
I can not understand where i made mistake. I think that this approach does not have an error.
06.18.17
What boundary conditions did you use to derive this equation for $T$?
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